Program to check Palindrome or not

In this example, We will learn a program to check Palindrome. We will check a number whether it is palindrome or not.

Palindrome Number is a number whose inverse is equal to the original number. Below number is a palindrome number.

151, 232, 1221 are palindrome numbers.

Application: Learn C Programming with Live Compiler

Learn C programming directly from mobile. This app includes tutorials with topics, examples and live compiler.

To understand this example, You must have knowledge in following topics

• Introduction
• While Loop

Algorithm

The algorithm of program to check whether number is palindrome or not is given below

Step 1: Start
Step 2: Initialize the variables a, b, c, s = 0
Step 3: Take input from user and assign to a
Step 4: c = a
Step 5: Repeat this STEP if a > 0
           Step 5.1: b = a % 10
           Step 5.2: s = ( s * 10 ) + b
           Step 5.3: a = a / 10
Step 6: IF (s == c) THEN
           Step 6.1: Number is a palindrome
Step 7: ELSE
           Step 7.1: Number is not a palindrome
Step 8: End

Flowchart

The flowchart of program to check whether number is palindrome or not is given below

CODE: Program to Check Palindrome

Now, We will look on the code to check palindrome.

#include<stdio.h>

void main(){
    
    int a, b, c, s = 0;
    
    printf("Enter a number:\t");
    scanf("%d", &a);
    c = a;

    // the number is reversed inside the while loop.
    while(a > 0){
        b = a % 10;
        s = ( s * 10 ) + b;
        a = a / 10;
    }

    // here the reversed number is compared with the given number.
    if(s == c)
        printf("%d is a palindrome", c);
    else
        printf("%d is not a palindrome", c);
   
}

The output of above program is

Enter a number: 151
151 is a palindrome

Enter a number: 12
12 is not a palindrome